Example 1. Putting a value in
Work out 8 × (x + 3) when x = 2.
Solution
- Put 2 where the x is: 8 × (2 + 3).
- Brackets first: 2 + 3 = 5.
- Now multiply: 8 × 5 = 40.
40
Chapter 08
This is the chapter the course is named for. In arithmetic you are given all the numbers and you work out the answer. Here one of the numbers is missing, and a letter stands in its place until it is found.
Everything else stays the same, because the rules that apply to numbers apply to the letter standing in for one.
A variable is a letter that stands for a number. An expression is numbers, variables and operations with no equals sign. An equation has an equals sign in it.
Solving x + 5 = 12
Subtract 5 from both sides.
x = 12 − 5
x = 7
Much of pre-algebra is vocabulary. A question names what it wants in these terms, and the term decides which arithmetic answers it.
Each one is set out the way a solution is written on paper: the question, the steps in order, then the answer.
Work out 8 × (x + 3) when x = 2.
Solution
40
If x = 6, what is x + 4?
Solution
10
If y = 4, what is 3y + 2?
Solution
14
If x = 3, what is 2x + 5?
Solution
11
Two boards. The first solves an equation with one letter in it. The second puts a value in place of the letter and works the expression out. Both show every step, and both keep fractions exact, so a third is 1/3 here and not 0.333333333333, which is how you are expected to write it.
One letter, one answer, and every step it took to get there.
Give the letter a value, and see the substitution before the answer.